12(y-200)+16y=4y-2100

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Solution for 12(y-200)+16y=4y-2100 equation: 



12(y-200)+16y=4y-2100

We move all terms to the left:

12(y-200)+16y-(4y-2100)=0

We add all the numbers together, and all the variables

16y+12(y-200)-(4y-2100)=0

We multiply parentheses

16y+12y-(4y-2100)-2400=0

We get rid of parentheses

16y+12y-4y+2100-2400=0

We add all the numbers together, and all the variables

24y-300=0

We move all terms containing y to the left, all other terms to the right

24y=300

y=300/24

y=12+1/2

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