12(y-300)+8y=10y-50

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Solution for 12(y-300)+8y=10y-50 equation: 



12(y-300)+8y=10y-50

We move all terms to the left:

12(y-300)+8y-(10y-50)=0

We add all the numbers together, and all the variables

8y+12(y-300)-(10y-50)=0

We multiply parentheses

8y+12y-(10y-50)-3600=0

We get rid of parentheses

8y+12y-10y+50-3600=0

We add all the numbers together, and all the variables

10y-3550=0

We move all terms containing y to the left, all other terms to the right

10y=3550

y=3550/10

y=355

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