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12(y-4)+10=2(2y+5)+24
We move all terms to the left:
12(y-4)+10-(2(2y+5)+24)=0
We multiply parentheses
12y-(2(2y+5)+24)-48+10=0
We calculate terms in parentheses: -(2(2y+5)+24), so:We add all the numbers together, and all the variables
2(2y+5)+24
We multiply parentheses
4y+10+24
We add all the numbers together, and all the variables
4y+34
Back to the equation:
-(4y+34)
12y-(4y+34)-38=0
We get rid of parentheses
12y-4y-34-38=0
We add all the numbers together, and all the variables
8y-72=0
We move all terms containing y to the left, all other terms to the right
8y=72
y=72/8
y=9
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