12(y-4)+10=2(2y+5)+24

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Solution for 12(y-4)+10=2(2y+5)+24 equation: 



12(y-4)+10=2(2y+5)+24

We move all terms to the left:

12(y-4)+10-(2(2y+5)+24)=0

We multiply parentheses

12y-(2(2y+5)+24)-48+10=0



We calculate terms in parentheses: -(2(2y+5)+24), so:

2(2y+5)+24

We multiply parentheses

4y+10+24

We add all the numbers together, and all the variables

4y+34

Back to the equation:

-(4y+34)



We add all the numbers together, and all the variables

12y-(4y+34)-38=0

We get rid of parentheses

12y-4y-34-38=0

We add all the numbers together, and all the variables

8y-72=0

We move all terms containing y to the left, all other terms to the right

8y=72

y=72/8

y=9

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