12(y-5)-10(y+2)=32

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Solution for 12(y-5)-10(y+2)=32 equation:


Simplifying
12(y + -5) + -10(y + 2) = 32

Reorder the terms:
12(-5 + y) + -10(y + 2) = 32
(-5 * 12 + y * 12) + -10(y + 2) = 32
(-60 + 12y) + -10(y + 2) = 32

Reorder the terms:
-60 + 12y + -10(2 + y) = 32
-60 + 12y + (2 * -10 + y * -10) = 32
-60 + 12y + (-20 + -10y) = 32

Reorder the terms:
-60 + -20 + 12y + -10y = 32

Combine like terms: -60 + -20 = -80
-80 + 12y + -10y = 32

Combine like terms: 12y + -10y = 2y
-80 + 2y = 32

Solving
-80 + 2y = 32

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '80' to each side of the equation.
-80 + 80 + 2y = 32 + 80

Combine like terms: -80 + 80 = 0
0 + 2y = 32 + 80
2y = 32 + 80

Combine like terms: 32 + 80 = 112
2y = 112

Divide each side by '2'.
y = 56

Simplifying
y = 56

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