12(z+12)=152

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Solution for 12(z+12)=152 equation: 



12(z+12)=152

We move all terms to the left:

12(z+12)-(152)=0

We multiply parentheses

12z+144-152=0

We add all the numbers together, and all the variables

12z-8=0

We move all terms containing z to the left, all other terms to the right

12z=8

z=8/12

z=2/3

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