12(z+2)-3(z-2)=5(z-2)+3(z-2)

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Solution for 12(z+2)-3(z-2)=5(z-2)+3(z-2) equation: 



12(z+2)-3(z-2)=5(z-2)+3(z-2)

We move all terms to the left:

12(z+2)-3(z-2)-(5(z-2)+3(z-2))=0

We multiply parentheses

12z-3z-(5(z-2)+3(z-2))+24+6=0



We calculate terms in parentheses: -(5(z-2)+3(z-2)), so:

5(z-2)+3(z-2)

We multiply parentheses

5z+3z-10-6

We add all the numbers together, and all the variables

8z-16

Back to the equation:

-(8z-16)



We add all the numbers together, and all the variables

9z-(8z-16)+30=0

We get rid of parentheses

9z-8z+16+30=0

We add all the numbers together, and all the variables

z+46=0

We move all terms containing z to the left, all other terms to the right

z=-46

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