12(z+2)-4(z-1)=4(z-1)+3(z-2)

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Solution for 12(z+2)-4(z-1)=4(z-1)+3(z-2) equation: 


Simplifying
12(z + 2) + -4(z + -1) = 4(z + -1) + 3(z + -2)

Reorder the terms:
12(2 + z) + -4(z + -1) = 4(z + -1) + 3(z + -2)
(2 * 12 + z * 12) + -4(z + -1) = 4(z + -1) + 3(z + -2)
(24 + 12z) + -4(z + -1) = 4(z + -1) + 3(z + -2)

Reorder the terms:
24 + 12z + -4(-1 + z) = 4(z + -1) + 3(z + -2)
24 + 12z + (-1 * -4 + z * -4) = 4(z + -1) + 3(z + -2)
24 + 12z + (4 + -4z) = 4(z + -1) + 3(z + -2)

Reorder the terms:
24 + 4 + 12z + -4z = 4(z + -1) + 3(z + -2)

Combine like terms: 24 + 4 = 28
28 + 12z + -4z = 4(z + -1) + 3(z + -2)

Combine like terms: 12z + -4z = 8z
28 + 8z = 4(z + -1) + 3(z + -2)

Reorder the terms:
28 + 8z = 4(-1 + z) + 3(z + -2)
28 + 8z = (-1 * 4 + z * 4) + 3(z + -2)
28 + 8z = (-4 + 4z) + 3(z + -2)

Reorder the terms:
28 + 8z = -4 + 4z + 3(-2 + z)
28 + 8z = -4 + 4z + (-2 * 3 + z * 3)
28 + 8z = -4 + 4z + (-6 + 3z)

Reorder the terms:
28 + 8z = -4 + -6 + 4z + 3z

Combine like terms: -4 + -6 = -10
28 + 8z = -10 + 4z + 3z

Combine like terms: 4z + 3z = 7z
28 + 8z = -10 + 7z

Solving
28 + 8z = -10 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
28 + 8z + -7z = -10 + 7z + -7z

Combine like terms: 8z + -7z = 1z
28 + 1z = -10 + 7z + -7z

Combine like terms: 7z + -7z = 0
28 + 1z = -10 + 0
28 + 1z = -10

Add '-28' to each side of the equation.
28 + -28 + 1z = -10 + -28

Combine like terms: 28 + -28 = 0
0 + 1z = -10 + -28
1z = -10 + -28

Combine like terms: -10 + -28 = -38
1z = -38

Divide each side by '1'.
z = -38

Simplifying
z = -38

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