12(z+3)-3(z-2)=3(z-1)+5(z-2)

Solution for 12(z+3)-3(z-2)=3(z-1)+5(z-2) equation:

12(z+3)-3(z-2)=3(z-1)+5(z-2)

We move all terms to the left:

12(z+3)-3(z-2)-(3(z-1)+5(z-2))=0

We multiply parentheses

12z-3z-(3(z-1)+5(z-2))+36+6=0


We calculate terms in parentheses: -(3(z-1)+5(z-2)), so:

3(z-1)+5(z-2)

We multiply parentheses

3z+5z-3-10

We add all the numbers together, and all the variables

8z-13

Back to the equation:

-(8z-13)


We add all the numbers together, and all the variables

9z-(8z-13)+42=0

We get rid of parentheses

9z-8z+13+42=0

We add all the numbers together, and all the variables

z+55=0

We move all terms containing z to the left, all other terms to the right

z=-55