12*(4x-5)=-11*(10x+10)+208

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Solution for 12*(4x-5)=-11*(10x+10)+208 equation: 



12(4x-5)=-11(10x+10)+208

We move all terms to the left:

12(4x-5)-(-11(10x+10)+208)=0

We multiply parentheses

48x-(-11(10x+10)+208)-60=0



We calculate terms in parentheses: -(-11(10x+10)+208), so:

-11(10x+10)+208

We multiply parentheses

-110x-110+208

We add all the numbers together, and all the variables

-110x+98

Back to the equation:

-(-110x+98)



We get rid of parentheses

48x+110x-98-60=0

We add all the numbers together, and all the variables

158x-158=0

We move all terms containing x to the left, all other terms to the right

158x=158

x=158/158

x=1

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