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12*10=(x+6)(x-1)
We move all terms to the left:
12*10-((x+6)(x-1))=0
We add all the numbers together, and all the variables
-((x+6)(x-1))+120=0
We multiply parentheses ..
-((+x^2-1x+6x-6))+120=0
We calculate terms in parentheses: -((+x^2-1x+6x-6)), so:We get rid of parentheses
(+x^2-1x+6x-6)
We get rid of parentheses
x^2-1x+6x-6
We add all the numbers together, and all the variables
x^2+5x-6
Back to the equation:
-(x^2+5x-6)
-x^2-5x+6+120=0
We add all the numbers together, and all the variables
-1x^2-5x+126=0
a = -1; b = -5; c = +126;
Δ = b2-4ac
Δ = -52-4·(-1)·126
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-23}{2*-1}=\frac{-18}{-2} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+23}{2*-1}=\frac{28}{-2} =-14 $
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