12*4+2b/9b-3=42 - solution

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Solution for 12*4+2b/9b-3=42 equation:

b in (-oo:+oo)

((2*b)/9)*b+4*12-3 = 42 // - 42

((2*b)/9)*b+4*12-42-3 = 0

2/9*b^2 = -3 // : 2/9

b^2 = -27/2

b belongs to the empty set

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