12+(3-9x)=16-(3x+9)

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Solution for 12+(3-9x)=16-(3x+9) equation: 



12+(3-9x)=16-(3x+9)

We move all terms to the left:

12+(3-9x)-(16-(3x+9))=0

We add all the numbers together, and all the variables

(-9x+3)-(16-(3x+9))+12=0

We get rid of parentheses

-9x-(16-(3x+9))+3+12=0



We calculate terms in parentheses: -(16-(3x+9)), so:

16-(3x+9)

determiningTheFunctionDomain
-(3x+9)+16

We get rid of parentheses

-3x-9+16

We add all the numbers together, and all the variables

-3x+7

Back to the equation:

-(-3x+7)



We add all the numbers together, and all the variables

-9x-(-3x+7)+15=0

We get rid of parentheses

-9x+3x-7+15=0

We add all the numbers together, and all the variables

-6x+8=0

We move all terms containing x to the left, all other terms to the right

-6x=-8

x=-8/-6

x=1+1/3

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