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12+(x+2)=2x+(x+4)+6
We move all terms to the left:
12+(x+2)-(2x+(x+4)+6)=0
We get rid of parentheses
x-(2x+(x+4)+6)+2+12=0
We calculate terms in parentheses: -(2x+(x+4)+6), so:We add all the numbers together, and all the variables
2x+(x+4)+6
We get rid of parentheses
2x+x+4+6
We add all the numbers together, and all the variables
3x+10
Back to the equation:
-(3x+10)
x-(3x+10)+14=0
We get rid of parentheses
x-3x-10+14=0
We add all the numbers together, and all the variables
-2x+4=0
We move all terms containing x to the left, all other terms to the right
-2x=-4
x=-4/-2
x=+2
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