12+1/4m+1/2m-15=-18

Solution for 12+1/4m+1/2m-15=-18 equation:

12+1/4m+1/2m-15=-18

We move all terms to the left:

12+1/4m+1/2m-15-(-18)=0


Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R



Domain of the equation: 2m!=0

m!=0/2

m!=0

m∈R


We add all the numbers together, and all the variables

1/4m+1/2m+15=0

We calculate fractions


2m/8m^2+4m/8m^2+15=0

We multiply all the terms by the denominator


2m+4m+15*8m^2=0

We add all the numbers together, and all the variables

6m+15*8m^2=0

Wy multiply elements

120m^2+6m=0

a = 120; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·120·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*120}=\frac{-12}{240}
=-1/20
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*120}=\frac{0}{240}
=0
$