12+1/4x-15-(-18-1/2x)=0

Solution for 12+1/4x-15-(-18-1/2x)=0 equation:

12+1/4x-15-(-18-1/2x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/4x-(-1/2x-18)+12-15=0

We add all the numbers together, and all the variables

1/4x-(-1/2x-18)-3=0

We get rid of parentheses

1/4x+1/2x+18-3=0

We calculate fractions


2x/8x^2+4x/8x^2+18-3=0

We add all the numbers together, and all the variables

2x/8x^2+4x/8x^2+15=0

We multiply all the terms by the denominator


2x+4x+15*8x^2=0

We add all the numbers together, and all the variables

6x+15*8x^2=0

Wy multiply elements

120x^2+6x=0

a = 120; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·120·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*120}=\frac{-12}{240}
=-1/20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*120}=\frac{0}{240}
=0
$