If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12+1/5r=2r+1
We move all terms to the left:
12+1/5r-(2r+1)=0
Domain of the equation: 5r!=0We get rid of parentheses
r!=0/5
r!=0
r∈R
1/5r-2r-1+12=0
We multiply all the terms by the denominator
-2r*5r-1*5r+12*5r+1=0
Wy multiply elements
-10r^2-5r+60r+1=0
We add all the numbers together, and all the variables
-10r^2+55r+1=0
a = -10; b = 55; c = +1;
Δ = b2-4ac
Δ = 552-4·(-10)·1
Δ = 3065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-\sqrt{3065}}{2*-10}=\frac{-55-\sqrt{3065}}{-20} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+\sqrt{3065}}{2*-10}=\frac{-55+\sqrt{3065}}{-20} $
| b-97=-b-7 | | 3/2=x/14 | | 25x=6x+1 | | 256+r^2=r^2+16r+64 | | -c-5=c+81 | | 4z/10+1=8 | | 2=4b(5+1)+b | | n-38=-n-8 | | -b+7=b+93 | | 8-3b=3b+2 | | p+54=-p+6 | | (x+10)(x+14)=(x+14)(x-10) | | y=((10/7)^(1/14))-15 | | 12x15=3x | | y=(10/7)^(1/14)-15 | | 3(v-14)+7(v-12)=14 | | 302.6=-1.02060061*366.27+b | | 17a=3(7-a)-1 | | 19+3x=3-5x | | 6x3–9x2–12x=0 | | 2z/7+4=-3 | | 9-9(x+2)^2=0 | | 6+-x2=14 | | z/7+7=2 | | 3x+1/7-2-4x/3=5x-4/14+7x/16 | | 7x/7x=1 | | 4x-2/3=5x-1/2 | | 0=x/2 | | (3t+3)5=6 | | 125/100=60/x | | 5x+8x=26/13 | | 3m+3=21m= |