12+2(3x-2)=40

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Solution for 12+2(3x-2)=40 equation: 



12+2(3x-2)=40

We move all terms to the left:

12+2(3x-2)-(40)=0

We add all the numbers together, and all the variables

2(3x-2)-28=0

We multiply parentheses

6x-4-28=0

We add all the numbers together, and all the variables

6x-32=0

We move all terms containing x to the left, all other terms to the right

6x=32

x=32/6

x=5+1/3

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