12+2(y+3)=24

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Solution for 12+2(y+3)=24 equation: 



12+2(y+3)=24

We move all terms to the left:

12+2(y+3)-(24)=0

We add all the numbers together, and all the variables

2(y+3)-12=0

We multiply parentheses

2y+6-12=0

We add all the numbers together, and all the variables

2y-6=0

We move all terms containing y to the left, all other terms to the right

2y=6

y=6/2

y=3

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