12+2(z-6)=-7z+4

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Solution for 12+2(z-6)=-7z+4 equation: 



12+2(z-6)=-7z+4

We move all terms to the left:

12+2(z-6)-(-7z+4)=0

We multiply parentheses

2z-(-7z+4)-12+12=0

We get rid of parentheses

2z+7z-4-12+12=0

We add all the numbers together, and all the variables

9z-4=0

We move all terms containing z to the left, all other terms to the right

9z=4

z=4/9

z=4/9

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