12+2m=5-5(4+5m)

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Solution for 12+2m=5-5(4+5m) equation: 



12+2m=5-5(4+5m)

We move all terms to the left:

12+2m-(5-5(4+5m))=0

We add all the numbers together, and all the variables

2m-(5-5(5m+4))+12=0



We calculate terms in parentheses: -(5-5(5m+4)), so:

5-5(5m+4)

determiningTheFunctionDomain
-5(5m+4)+5

We multiply parentheses

-25m-20+5

We add all the numbers together, and all the variables

-25m-15

Back to the equation:

-(-25m-15)



We get rid of parentheses

2m+25m+15+12=0

We add all the numbers together, and all the variables

27m+27=0

We move all terms containing m to the left, all other terms to the right

27m=-27

m=-27/27

m=-1

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