12+2n-4=4(n+3)-2n-4

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Solution for 12+2n-4=4(n+3)-2n-4 equation: 



12+2n-4=4(n+3)-2n-4

We move all terms to the left:

12+2n-4-(4(n+3)-2n-4)=0

We add all the numbers together, and all the variables

2n-(4(n+3)-2n-4)+8=0



We calculate terms in parentheses: -(4(n+3)-2n-4), so:

4(n+3)-2n-4

We add all the numbers together, and all the variables

-2n+4(n+3)-4

We multiply parentheses

-2n+4n+12-4

We add all the numbers together, and all the variables

2n+8

Back to the equation:

-(2n+8)



We get rid of parentheses

2n-2n-8+8=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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