12+3(2x-4)=3x+15

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Solution for 12+3(2x-4)=3x+15 equation: 



12+3(2x-4)=3x+15

We move all terms to the left:

12+3(2x-4)-(3x+15)=0

We multiply parentheses

6x-(3x+15)-12+12=0

We get rid of parentheses

6x-3x-15-12+12=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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