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12+3(2x-6)=6(1+x)
We move all terms to the left:
12+3(2x-6)-(6(1+x))=0
We add all the numbers together, and all the variables
3(2x-6)-(6(x+1))+12=0
We multiply parentheses
6x-(6(x+1))-18+12=0
We calculate terms in parentheses: -(6(x+1)), so:We add all the numbers together, and all the variables
6(x+1)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
6x-(6x+6)-6=0
We get rid of parentheses
6x-6x-6-6=0
We add all the numbers together, and all the variables
-12!=0
There is no solution for this equation
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