12+3(3z-1)=16z-12

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Solution for 12+3(3z-1)=16z-12 equation:



12+3(3z-1)=16z-12
We move all terms to the left:
12+3(3z-1)-(16z-12)=0
We multiply parentheses
9z-(16z-12)-3+12=0
We get rid of parentheses
9z-16z+12-3+12=0
We add all the numbers together, and all the variables
-7z+21=0
We move all terms containing z to the left, all other terms to the right
-7z=-21
z=-21/-7
z=+3

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