12+3(4y-1)=13+12y-4

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Solution for 12+3(4y-1)=13+12y-4 equation: 



12+3(4y-1)=13+12y-4

We move all terms to the left:

12+3(4y-1)-(13+12y-4)=0

We add all the numbers together, and all the variables

3(4y-1)-(12y+9)+12=0

We multiply parentheses

12y-(12y+9)-3+12=0

We get rid of parentheses

12y-12y-9-3+12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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