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12+3(x+1)=6x
We move all terms to the left:
12+3(x+1)-(6x)=0
We add all the numbers together, and all the variables
-6x+3(x+1)+12=0
We multiply parentheses
-6x+3x+3+12=0
We add all the numbers together, and all the variables
-3x+15=0
We move all terms containing x to the left, all other terms to the right
-3x=-15
x=-15/-3
x=+5
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