12+3(x+2)=6(x-2)

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Solution for 12+3(x+2)=6(x-2) equation: 



12+3(x+2)=6(x-2)

We move all terms to the left:

12+3(x+2)-(6(x-2))=0

We multiply parentheses

3x-(6(x-2))+6+12=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

3x-(6x-12)+18=0

We get rid of parentheses

3x-6x+12+18=0

We add all the numbers together, and all the variables

-3x+30=0

We move all terms containing x to the left, all other terms to the right

-3x=-30

x=-30/-3

x=+10

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