12+3(x-4)-21=5(5-4(4-4x))

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Solution for 12+3(x-4)-21=5(5-4(4-4x)) equation: 



12+3(x-4)-21=55-4(4-4x)

We move all terms to the left:

12+3(x-4)-21-(55-4(4-4x))=0

We add all the numbers together, and all the variables

3(x-4)-(55-4(-4x+4))+12-21=0

We add all the numbers together, and all the variables

3(x-4)-(55-4(-4x+4))-9=0

We multiply parentheses

3x-(55-4(-4x+4))-12-9=0



We calculate terms in parentheses: -(55-4(-4x+4)), so:

55-4(-4x+4)

determiningTheFunctionDomain
-4(-4x+4)+55

We multiply parentheses

16x-16+55

We add all the numbers together, and all the variables

16x+39

Back to the equation:

-(16x+39)



We add all the numbers together, and all the variables

3x-(16x+39)-21=0

We get rid of parentheses

3x-16x-39-21=0

We add all the numbers together, and all the variables

-13x-60=0

We move all terms containing x to the left, all other terms to the right

-13x=60

x=60/-13

x=-4+8/13

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