12+3(z-4)=-3z+5

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Solution for 12+3(z-4)=-3z+5 equation: 



12+3(z-4)=-3z+5

We move all terms to the left:

12+3(z-4)-(-3z+5)=0

We multiply parentheses

3z-(-3z+5)-12+12=0

We get rid of parentheses

3z+3z-5-12+12=0

We add all the numbers together, and all the variables

6z-5=0

We move all terms containing z to the left, all other terms to the right

6z=5

z=5/6

z=5/6

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