12+3/5m=27

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Solution for 12+3/5m=27 equation:



12+3/5m=27
We move all terms to the left:
12+3/5m-(27)=0
Domain of the equation: 5m!=0
m!=0/5
m!=0
m∈R
We add all the numbers together, and all the variables
3/5m-15=0
We multiply all the terms by the denominator
-15*5m+3=0
Wy multiply elements
-75m+3=0
We move all terms containing m to the left, all other terms to the right
-75m=-3
m=-3/-75
m=1/25

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