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12+3/5x=-27
We move all terms to the left:
12+3/5x-(-27)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/5x+39=0
We multiply all the terms by the denominator
39*5x+3=0
Wy multiply elements
195x+3=0
We move all terms containing x to the left, all other terms to the right
195x=-3
x=-3/195
x=-1/65
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