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12+3/5y=39
We move all terms to the left:
12+3/5y-(39)=0
Domain of the equation: 5y!=0We add all the numbers together, and all the variables
y!=0/5
y!=0
y∈R
3/5y-27=0
We multiply all the terms by the denominator
-27*5y+3=0
Wy multiply elements
-135y+3=0
We move all terms containing y to the left, all other terms to the right
-135y=-3
y=-3/-135
y=1/45
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