12+3x=3(-x+9)-33

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Solution for 12+3x=3(-x+9)-33 equation: 



12+3x=3(-x+9)-33

We move all terms to the left:

12+3x-(3(-x+9)-33)=0

We add all the numbers together, and all the variables

3x-(3(-1x+9)-33)+12=0



We calculate terms in parentheses: -(3(-1x+9)-33), so:

3(-1x+9)-33

We multiply parentheses

-3x+27-33

We add all the numbers together, and all the variables

-3x-6

Back to the equation:

-(-3x-6)



We get rid of parentheses

3x+3x+6+12=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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