12+4(b-3)=-8

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Solution for 12+4(b-3)=-8 equation: 



12+4(b-3)=-8

We move all terms to the left:

12+4(b-3)-(-8)=0

We add all the numbers together, and all the variables

4(b-3)+20=0

We multiply parentheses

4b-12+20=0

We add all the numbers together, and all the variables

4b+8=0

We move all terms containing b to the left, all other terms to the right

4b=-8

b=-8/4

b=-2

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