12+4(m-3)=6(3-m)

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Solution for 12+4(m-3)=6(3-m) equation: 



12+4(m-3)=6(3-m)

We move all terms to the left:

12+4(m-3)-(6(3-m))=0

We add all the numbers together, and all the variables

4(m-3)-(6(-1m+3))+12=0

We multiply parentheses

4m-(6(-1m+3))-12+12=0



We calculate terms in parentheses: -(6(-1m+3)), so:

6(-1m+3)

We multiply parentheses

-6m+18

Back to the equation:

-(-6m+18)



We add all the numbers together, and all the variables

4m-(-6m+18)=0

We get rid of parentheses

4m+6m-18=0

We add all the numbers together, and all the variables

10m-18=0

We move all terms containing m to the left, all other terms to the right

10m=18

m=18/10

m=1+4/5

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