12+4(m-4)=-2(m-1)-18

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Solution for 12+4(m-4)=-2(m-1)-18 equation: 



12+4(m-4)=-2(m-1)-18

We move all terms to the left:

12+4(m-4)-(-2(m-1)-18)=0

We multiply parentheses

4m-(-2(m-1)-18)-16+12=0



We calculate terms in parentheses: -(-2(m-1)-18), so:

-2(m-1)-18

We multiply parentheses

-2m+2-18

We add all the numbers together, and all the variables

-2m-16

Back to the equation:

-(-2m-16)



We add all the numbers together, and all the variables

4m-(-2m-16)-4=0

We get rid of parentheses

4m+2m+16-4=0

We add all the numbers together, and all the variables

6m+12=0

We move all terms containing m to the left, all other terms to the right

6m=-12

m=-12/6

m=-2

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