12+4(z-3)=4z+5

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Solution for 12+4(z-3)=4z+5 equation:


Simplifying
12 + 4(z + -3) = 4z + 5

Reorder the terms:
12 + 4(-3 + z) = 4z + 5
12 + (-3 * 4 + z * 4) = 4z + 5
12 + (-12 + 4z) = 4z + 5

Combine like terms: 12 + -12 = 0
0 + 4z = 4z + 5
4z = 4z + 5

Reorder the terms:
4z = 5 + 4z

Add '-4z' to each side of the equation.
4z + -4z = 5 + 4z + -4z

Combine like terms: 4z + -4z = 0
0 = 5 + 4z + -4z

Combine like terms: 4z + -4z = 0
0 = 5 + 0
0 = 5

Solving
0 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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