12+4x=6x+10-x2

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Solution for 12+4x=6x+10-x2 equation: 



12+4x=6x+10-x2

We move all terms to the left:

12+4x-(6x+10-x2)=0

We add all the numbers together, and all the variables

-(+6x-1x^2+10)+4x+12=0

We get rid of parentheses

1x^2-6x+4x-10+12=0

We add all the numbers together, and all the variables

x^2-2x+2=0

a = 1; b = -2; c = +2;
Δ = b2-4ac
Δ = -22-4·1·2
Δ = -4
Delta is less than zero, so there is no solution for the equation

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