12+4x=6x2+

Solution for 12+4x=6x2+ equation:

12+4x=6x^2+

We move all terms to the left:

12+4x-(6x^2+)=0

We get rid of parentheses

-6x^2+4x+12-=0

We add all the numbers together, and all the variables

-6x^2+4x=0

a = -6; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-6)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-6}=\frac{-8}{-12}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-6}=\frac{0}{-12}
=0
$