12+8(x+3)+7=3+4(2-x)+12

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Solution for 12+8(x+3)+7=3+4(2-x)+12 equation: 



12+8(x+3)+7=3+4(2-x)+12

We move all terms to the left:

12+8(x+3)+7-(3+4(2-x)+12)=0

We add all the numbers together, and all the variables

8(x+3)-(3+4(-1x+2)+12)+12+7=0

We add all the numbers together, and all the variables

8(x+3)-(3+4(-1x+2)+12)+19=0

We multiply parentheses

8x-(3+4(-1x+2)+12)+24+19=0



We calculate terms in parentheses: -(3+4(-1x+2)+12), so:

3+4(-1x+2)+12

determiningTheFunctionDomain
4(-1x+2)+3+12

We add all the numbers together, and all the variables

4(-1x+2)+15

We multiply parentheses

-4x+8+15

We add all the numbers together, and all the variables

-4x+23

Back to the equation:

-(-4x+23)



We add all the numbers together, and all the variables

8x-(-4x+23)+43=0

We get rid of parentheses

8x+4x-23+43=0

We add all the numbers together, and all the variables

12x+20=0

We move all terms containing x to the left, all other terms to the right

12x=-20

x=-20/12

x=-1+2/3

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