12+96/3x2x2x2=x

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Solution for 12+96/3x2x2x2=x equation: 



12+96/3x^2x2x^2=x

We move all terms to the left:

12+96/3x^2x2x^2-(x)=0



Domain of the equation: 3x^2x2x^2!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-1x+96/3x^2x2x^2+12=0

We multiply all the terms by the denominator


-1x*3x^2x2x^2+12*3x^2x2x^2+96=0

Wy multiply elements

-3x^3+36x^2+96=0

We do not support expression: x^3

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