12+X=2x2

Solution for 12+X=2x2 equation:

12+X=2X^2

We move all terms to the left:

12+X-(2X^2)=0

determiningTheFunctionDomain
-2X^2+X+12=0

a = -2; b = 1; c = +12;
Δ = b2-4ac
Δ = 12-4·(-2)·12
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{97}}{2*-2}=\frac{-1-\sqrt{97}}{-4}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{97}}{2*-2}=\frac{-1+\sqrt{97}}{-4}
$