12+x+(x-2)+3=141

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Solution for 12+x+(x-2)+3=141 equation: 



12+x+(x-2)+3=141

We move all terms to the left:

12+x+(x-2)+3-(141)=0

We add all the numbers together, and all the variables

x+(x-2)-126=0

We get rid of parentheses

x+x-2-126=0

We add all the numbers together, and all the variables

2x-128=0

We move all terms containing x to the left, all other terms to the right

2x=128

x=128/2

x=64

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