12-(1/8)y=19+(3/4)y

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Solution for 12-(1/8)y=19+(3/4)y equation: 



12-(1/8)y=19+(3/4)y

We move all terms to the left:

12-(1/8)y-(19+(3/4)y)=0



Domain of the equation: 8)y!=0

y!=0/1

y!=0

y∈R





Domain of the equation: 4)y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

-(+1/8)y-(19+(+3/4)y)+12=0

We multiply parentheses

-y^2-(19+(+3/4)y)+12=0

We multiply all the terms by the denominator


-y^2*4)y)-(19+(+12*4)y)+3=0

We add all the numbers together, and all the variables

-y^2*4)y)-(19+48y)+3=0

Wy multiply elements

-4y^3=0

We do not support eypression: y^3

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