12-(16x+3)-4x=-4(10x+4)-3(5)

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Solution for 12-(16x+3)-4x=-4(10x+4)-3(5) equation: 



12-(16x+3)-4x=-4(10x+4)-3(5)

We move all terms to the left:

12-(16x+3)-4x-(-4(10x+4)-3(5))=0

We add all the numbers together, and all the variables

-4x-(16x+3)-(-4(10x+4)-35)+12=0

We get rid of parentheses

-4x-16x-(-4(10x+4)-35)-3+12=0



We calculate terms in parentheses: -(-4(10x+4)-35), so:

-4(10x+4)-35

We multiply parentheses

-40x-16-35

We add all the numbers together, and all the variables

-40x-51

Back to the equation:

-(-40x-51)



We add all the numbers together, and all the variables

-20x-(-40x-51)+9=0

We get rid of parentheses

-20x+40x+51+9=0

We add all the numbers together, and all the variables

20x+60=0

We move all terms containing x to the left, all other terms to the right

20x=-60

x=-60/20

x=-3

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