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12-(2x/3+x)=2
We move all terms to the left:
12-(2x/3+x)-(2)=0
Domain of the equation: 3+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x)!=-3
x!=-3/1
x!=-3
x∈R
-(+x+2x/3)+12-2=0
We add all the numbers together, and all the variables
-(+x+2x/3)+10=0
We get rid of parentheses
-x-2x/3+10=0
We multiply all the terms by the denominator
-x*3-2x+10*3=0
We add all the numbers together, and all the variables
-2x-x*3+30=0
Wy multiply elements
-2x-3x+30=0
We add all the numbers together, and all the variables
-5x+30=0
We move all terms containing x to the left, all other terms to the right
-5x=-30
x=-30/-5
x=+6
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