12-(3x-6)+12=4(x-5)-3(2x-1)+12

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Solution for 12-(3x-6)+12=4(x-5)-3(2x-1)+12 equation: 



12-(3x-6)+12=4(x-5)-3(2x-1)+12

We move all terms to the left:

12-(3x-6)+12-(4(x-5)-3(2x-1)+12)=0

We add all the numbers together, and all the variables

-(3x-6)-(4(x-5)-3(2x-1)+12)+24=0

We get rid of parentheses

-3x-(4(x-5)-3(2x-1)+12)+6+24=0



We calculate terms in parentheses: -(4(x-5)-3(2x-1)+12), so:

4(x-5)-3(2x-1)+12

We multiply parentheses

4x-6x-20+3+12

We add all the numbers together, and all the variables

-2x-5

Back to the equation:

-(-2x-5)



We add all the numbers together, and all the variables

-3x-(-2x-5)+30=0

We get rid of parentheses

-3x+2x+5+30=0

We add all the numbers together, and all the variables

-1x+35=0

We move all terms containing x to the left, all other terms to the right

-x=-35

x=-35/-1

x=+35

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