12-(4-4n)+17n=-6+18(n+1)

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Solution for 12-(4-4n)+17n=-6+18(n+1) equation: 



12-(4-4n)+17n=-6+18(n+1)

We move all terms to the left:

12-(4-4n)+17n-(-6+18(n+1))=0

We add all the numbers together, and all the variables

-(-4n+4)+17n-(-6+18(n+1))+12=0

We add all the numbers together, and all the variables

17n-(-4n+4)-(-6+18(n+1))+12=0

We get rid of parentheses

17n+4n-(-6+18(n+1))-4+12=0



We calculate terms in parentheses: -(-6+18(n+1)), so:

-6+18(n+1)

determiningTheFunctionDomain
18(n+1)-6

We multiply parentheses

18n+18-6

We add all the numbers together, and all the variables

18n+12

Back to the equation:

-(18n+12)



We add all the numbers together, and all the variables

21n-(18n+12)+8=0

We get rid of parentheses

21n-18n-12+8=0

We add all the numbers together, and all the variables

3n-4=0

We move all terms containing n to the left, all other terms to the right

3n=4

n=4/3

n=1+1/3

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