12-(4/5)x+15=4

Solution for 12-(4/5)x+15=4 equation:

12-(4/5)x+15=4

We move all terms to the left:

12-(4/5)x+15-(4)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(+4/5)x+12+15-4=0

We add all the numbers together, and all the variables

-(+4/5)x+23=0

We multiply parentheses

-4x^2+23=0

a = -4; b = 0; c = +23;
Δ = b2-4ac
Δ = 02-4·(-4)·23
Δ = 368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{368}=\sqrt{16*23}=\sqrt{16}*\sqrt{23}=4\sqrt{23}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{23}}{2*-4}=\frac{0-4\sqrt{23}}{-8}
=-\frac{4\sqrt{23}}{-8}
=-\frac{\sqrt{23}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{23}}{2*-4}=\frac{0+4\sqrt{23}}{-8}
=\frac{4\sqrt{23}}{-8}
=\frac{\sqrt{23}}{-2}
$