12-(4x+1)=6(x-3)+2

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Solution for 12-(4x+1)=6(x-3)+2 equation: 



12-(4x+1)=6(x-3)+2

We move all terms to the left:

12-(4x+1)-(6(x-3)+2)=0

We get rid of parentheses

-4x-(6(x-3)+2)-1+12=0



We calculate terms in parentheses: -(6(x-3)+2), so:

6(x-3)+2

We multiply parentheses

6x-18+2

We add all the numbers together, and all the variables

6x-16

Back to the equation:

-(6x-16)



We add all the numbers together, and all the variables

-4x-(6x-16)+11=0

We get rid of parentheses

-4x-6x+16+11=0

We add all the numbers together, and all the variables

-10x+27=0

We move all terms containing x to the left, all other terms to the right

-10x=-27

x=-27/-10

x=2+7/10

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