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12-(4x+1)=6(x-3)+2
We move all terms to the left:
12-(4x+1)-(6(x-3)+2)=0
We get rid of parentheses
-4x-(6(x-3)+2)-1+12=0
We calculate terms in parentheses: -(6(x-3)+2), so:We add all the numbers together, and all the variables
6(x-3)+2
We multiply parentheses
6x-18+2
We add all the numbers together, and all the variables
6x-16
Back to the equation:
-(6x-16)
-4x-(6x-16)+11=0
We get rid of parentheses
-4x-6x+16+11=0
We add all the numbers together, and all the variables
-10x+27=0
We move all terms containing x to the left, all other terms to the right
-10x=-27
x=-27/-10
x=2+7/10
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